Optimal. Leaf size=117 \[ \frac {3 (4 x+1)^{m+1} \, _2F_1\left (1,m+1;m+2;\frac {3 (4 x+1)}{13-2 \sqrt {13}}\right )}{\sqrt {13} \left (13-2 \sqrt {13}\right ) (m+1)}-\frac {3 (4 x+1)^{m+1} \, _2F_1\left (1,m+1;m+2;\frac {3 (4 x+1)}{13+2 \sqrt {13}}\right )}{\sqrt {13} \left (13+2 \sqrt {13}\right ) (m+1)} \]
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Rubi [A] time = 0.11, antiderivative size = 117, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 2, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.100, Rules used = {711, 68} \[ \frac {3 (4 x+1)^{m+1} \, _2F_1\left (1,m+1;m+2;\frac {3 (4 x+1)}{13-2 \sqrt {13}}\right )}{\sqrt {13} \left (13-2 \sqrt {13}\right ) (m+1)}-\frac {3 (4 x+1)^{m+1} \, _2F_1\left (1,m+1;m+2;\frac {3 (4 x+1)}{13+2 \sqrt {13}}\right )}{\sqrt {13} \left (13+2 \sqrt {13}\right ) (m+1)} \]
Antiderivative was successfully verified.
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Rule 68
Rule 711
Rubi steps
\begin {align*} \int \frac {(1+4 x)^m}{1-5 x+3 x^2} \, dx &=\int \left (-\frac {6 (1+4 x)^m}{\sqrt {13} \left (5+\sqrt {13}-6 x\right )}-\frac {6 (1+4 x)^m}{\sqrt {13} \left (-5+\sqrt {13}+6 x\right )}\right ) \, dx\\ &=-\frac {6 \int \frac {(1+4 x)^m}{5+\sqrt {13}-6 x} \, dx}{\sqrt {13}}-\frac {6 \int \frac {(1+4 x)^m}{-5+\sqrt {13}+6 x} \, dx}{\sqrt {13}}\\ &=\frac {3 (1+4 x)^{1+m} \, _2F_1\left (1,1+m;2+m;\frac {3 (1+4 x)}{13-2 \sqrt {13}}\right )}{\sqrt {13} \left (13-2 \sqrt {13}\right ) (1+m)}-\frac {3 (1+4 x)^{1+m} \, _2F_1\left (1,1+m;2+m;\frac {3 (1+4 x)}{13+2 \sqrt {13}}\right )}{\sqrt {13} \left (13+2 \sqrt {13}\right ) (1+m)}\\ \end {align*}
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Mathematica [A] time = 0.12, size = 94, normalized size = 0.80 \[ \frac {(4 x+1)^{m+1} \left (\left (13+2 \sqrt {13}\right ) \, _2F_1\left (1,m+1;m+2;\frac {12 x+3}{13-2 \sqrt {13}}\right )+\left (2 \sqrt {13}-13\right ) \, _2F_1\left (1,m+1;m+2;\frac {12 x+3}{13+2 \sqrt {13}}\right )\right )}{39 \sqrt {13} (m+1)} \]
Antiderivative was successfully verified.
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fricas [F] time = 1.01, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (4 \, x + 1\right )}^{m}}{3 \, x^{2} - 5 \, x + 1}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (4 \, x + 1\right )}^{m}}{3 \, x^{2} - 5 \, x + 1}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.14, size = 0, normalized size = 0.00 \[ \int \frac {\left (4 x +1\right )^{m}}{3 x^{2}-5 x +1}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (4 \, x + 1\right )}^{m}}{3 \, x^{2} - 5 \, x + 1}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\left (4\,x+1\right )}^m}{3\,x^2-5\,x+1} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (4 x + 1\right )^{m}}{3 x^{2} - 5 x + 1}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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